q^2=q/4

Solution for q^2=q/4 equation:

q^2=q/4

We move all terms to the left:

q^2-(q/4)=0

We add all the numbers together, and all the variables

q^2-(+q/4)=0

We get rid of parentheses

q^2-q/4=0

We multiply all the terms by the denominator


q^2*4-q=0

We add all the numbers together, and all the variables

q^2*4-1q=0

Wy multiply elements

4q^2-1q=0

a = 4; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·4·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*4}=\frac{0}{8}
=0
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*4}=\frac{2}{8}
=1/4
$